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Challenge The price of Stock A at 9 A.M. was $15.52. Since then, the price has been increasing at the rate of $0.13 each hour. At noon the price of Stock B was
$16.02. It begins to decrease at the rate of $0.11 each hour. If the two rates continue, in how many hours will the prices of the two stocks be the same?
In about I hours, the prices of the two stocks will be the same.
(Round to the nearest tenth as needed.)

Challenge The price of Stock A at 9 AM was 1552 Since then the price has been increasing at the rate of 013 each hour At noon the price of Stock B was 1602 It b class=

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lukelaws

Answer:   6 1/6 hours after 9 am, or 3 1/6 hours after noon

Step-by-step explanation:

If we count time (x) in hours after 9 am, the stock prices will be ...

 A = 16.15 +0.06x

 B = 16.90 -0.12(x -3)

The value of x when A = B can be found from ...

 A = B

 16.15 +0.06x = 16.90 -0.12(x -3)

 0.18x = 1.11 . . . . . . . . add 0.12x-16.15

 x = 6.16666...(repeating) = 6 1/6

6 1/6 hours after 9 am, the prices will be the same. That is 3 1/6 hours after noon.

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The attached graph shows the time as military time: 15.167. That's 3:10 pm, or 6 1/6 hours after 9 am.