The value of q is = 2.5x10⁻⁸C
Formula for electric potential at distance r
[tex]v = \frac{kq}{r}[/tex]
We have to find the radius of charge
[tex]A = 4pir^2[/tex]
[tex]r=\sqrt{\frac{A}{4pi} }[/tex]
A = 2.11
[tex]r= \sqrt{\frac{2.11m^2}{4*3.14} }[/tex]
r = 0.4096
The charge
[tex]V=\frac{kq}{r} \\\\q = \frac{vr}{k} \\\\q = \frac{549*0.4096}{8.99*10^9}[/tex]
q = 2.5x10⁻⁸C
What is the equipotential surface?
This is the surface that stands as the locus of points that have equal potentials.
Such a surface has the same electric potential at all of its points
Read more on equipotential surface
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