The mechanism for the reaction 2H2O2(aq) → 2H2O(l) + O2(g) in the presence of I–(aq) is proposed to be:
Step 1: H2O2(aq) + I–(aq) → H2O(l) + OI–(aq)
(slow)
Step 2: H2O2(aq) + OI–(aq) → H2O() + O2(g) + I–(aq)
(fast)

What is the intermediate?

Respuesta :

Answer:

rate: K' [H₂O₂]

Explanation:

The intermediate of the reaction is [tex]OI^{-}[/tex]. The intermediate involves slow step and intermediates are stable.

What is intermediate of a reaction ?

Reaction intermediate is a substance which appears in the middle step of a chemical reaction. An intermediate always formed in an first elementary step and consumed in a next elementary step.

A mechanism for the reaction with a slow step followed by a fast step:

Step 1: [tex]H_{2}O_{2} (aq) + I^{-} (aq)[/tex]  →  [tex]H_{2}O(l) + OI^{-} (aq)[/tex]  (Slow)

Step 2: [tex]H_{2}O_{2} (aq) + OI^{-} (aq)[/tex] → [tex]H_{2}O (l) + O_{2} (g) + I^{-} (aq)[/tex] (Fast)

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Overall Equation: [tex]2H_{2}O_{2}[/tex]  →  [tex]2H_{2}O + O_{2}[/tex]

Here the slow step is called the rate determining step.  We can see that Step 1 is the slowest step in the given reaction so Step 1 is the rate determining step. The formation of intermediate is the slowest step.  Reactants are not intermediates. The overall order of the reaction is 2.

[tex]OI^{-}[/tex] is the intermediate and [tex]I^{-}[/tex] is the catalyst.  

Rate = rate of slow step = [tex]k [H_{2}O_{2}] [I^{-}][/tex].

Thus we can conclude that in the given reaction [tex]OI^{-}[/tex] is the intermediate.

Learn more about the Chemical reaction here: https://brainly.com/question/11231920

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