A quadratic equation is the equation in which the unknown variable is one and the highest power of the unknown variable is two.
The quadratic form of the given equation is,
[tex]6u\timesu+4u^2+6=0[/tex]
Where,
[tex]u=(x-5)^2[/tex]
The option 4 is the correct option.
A quadratic equation is the equation in which the unknown variable is one and the highest power of the unknown variable is two.
The standard form of the quadratic equation is,
[tex]ax^2+bx+c=0[/tex]
Here, [tex]a,b,c[/tex] is the real numbers and [tex]x[/tex] is the variable.
Given information-
The given expression in the problem is,
[tex]6(x-5)^4+4(x-5)^2+6=0[/tex]
Rewrite the equation as,
[tex]6(x-5)^2\times(x-5)^2+4(x-5)^2+6=0[/tex]
Let,
[tex]u=(x-5)^2[/tex]
Then the given expression can be written as,
[tex]6u\timesu+4u^2+6=0[/tex]
Hence, the quadratic form of the given equation is,
[tex]6u\timesu+4u^2+6=0[/tex]
Where,
[tex]u=(x-5)^2[/tex]
The option 4 is the correct option.
Learn more about the quadratic equation here;
https://brainly.com/question/1214333
