What are the roots of the quadratic equation x^2 - 10 + 125? Please help! I'll give brainly to whoever gets the correct answer
A. x= -5 ± 5√6
B. x= -5 ± 10i
C. x= 5 ± 5√6
D. 5 ± 10i

Respuesta :

Answer:

D) [tex]x=5\pm10i[/tex]

Step-by-step explanation:

[tex]x^2-10x+125=0[/tex]

[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

[tex]x=\frac{-(-10)\pm\sqrt{(-10)^2-4(1)(125)}}{2(1)}[/tex]

[tex]x=\frac{10\pm\sqrt{100-500}}{2}[/tex]

[tex]x=\frac{10\pm\sqrt{-400}}{2}[/tex]

[tex]x=\frac{10\pm20i}{2}[/tex]

[tex]x=5\pm10i[/tex]

Therefore, the correct option is D

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