(1 point) Use differentials (or equivalently, a linear approximation) to approximate sin(56∘)
sin(56∘) as follows: Let ()=sin() and find the equation of the tangent line to () at a "nice" point near 56∘. Then use this to approximate sin(56∘).
Approximation =

Respuesta :

Linear approximations are used to estimate functions using derivatives

The approximated value of sin(56 degrees) is 0.8429

How to approximate sin(56)

The trigonometry expression is given as:

[tex]\sin(56^o)[/tex]

Convert 56 degrees to radians

[tex]56^o = \frac{56}{180}\pi[/tex]

To approximate, we make use of 45 degrees.

Where:

[tex]\sin(45^o) = \cos(45^o) = \frac{\sqrt 2}{2}[/tex]

Also, we have:

[tex]45^o= \frac{\pi}{4}[/tex]

And

[tex](\sin\ x)'= \cos\ x[/tex]

So, the approximation of sin(56 degrees) become:

[tex]\sin(56\°) = \sin(45\°) + (\frac{56}{180}\pi - \frac{\pi}{4}) *\cos(45\°)[/tex]

Substitute known values

[tex]\sin(56\°) = \frac{\sqrt 2}{2} + (\frac{56}{180}\pi - \frac{\pi}{4}) *\frac{\sqrt 2}{2}[/tex]

Take LCM

[tex]\sin(56\°) = \frac{\sqrt 2}{2} + \frac{56 - 45}{180}\pi *\frac{\sqrt 2}{2}[/tex]

[tex]\sin(56\°) = \frac{\sqrt 2}{2} + \frac{11}{180}\pi *\frac{\sqrt 2}{2}[/tex]

Solve the expression

[tex]\sin(56^o) = 0.8429[/tex]

Hence, the approximated value of sin(56 degrees) is 0.8429

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