The condition of two congruent angles in each triangle, can be used to
show that the two triangles are similar.
Response:
- Part 1: The two triangles are similar by AA similarity postulate
- Part 2: AC = 22.5 inches, AB = 30 inches
Which condition of similarity makes the two triangles similar?
Part 1:
A two column proof is presented as follows;
Statement [tex]{}[/tex] Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Reason
1. ∠D ≅ ∠A [tex]{}[/tex]                  1. Given
2. ∠DCE ≅ ∠ACB [tex]{}[/tex]             2. Vertical angle theorem
3. ΔCDE ~ ΔCAB [tex]{}[/tex]             3. AA similarity postulate
Angle-Angle, AA, similarity postulate states that if two angles in one
triangle are congruent to two angles in a second triangles, then the two
triangles are similar.
Part 2:
From part 1, we have;
ΔCDE is similar to ΔCAB (ΔCDE ~ ΔCAB)
The ratio of corresponding sides of similar triangles are equal, which
gives;
[tex]\dfrac{\overline{CD}}{\overline{AC}} = \mathbf{\dfrac{\overline{CE}}{\overline{CB}}}[/tex]
Which gives;
[tex]\dfrac{12}{\overline{AC}} = \mathbf{\dfrac{8}{15}}[/tex]
[tex]\overline{AC}} = \dfrac{15}{8} \times 12 = \mathbf{22.5}[/tex]
Similarly, we have;
[tex]\dfrac{\overline{DE}}{\overline{AB}} = \mathbf{\dfrac{\overline{CE}}{\overline{CB}}}[/tex]
Which gives;
[tex]\dfrac{16}{\overline{AB}} = \dfrac{8}{15}[/tex]
[tex]{\overline{AB}} = \dfrac{15}{8} \times 16 = \mathbf{30}[/tex]
Learn more about AA similarity postulate here:
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