The volume of the ball is 636.38 cm^3. Option C shows the correct volume of the ball.
The volume of the sphere is defined as the amount of space occupied within the sphere. It is a space occupied by a three-dimensional object.
Given that the thickness of the ball is 2 cm and the outer radius r2 of the ball is 6 cm. The inner radius r1 of the ball is the difference between the outer surface and the thickness of the material.
r1 = 6-2
r1 = 4cm
The volume of the sphere ball is given as,
[tex]V = \dfrac {4}{3}\pi r^3[/tex]
For the inner radius, the volume is given as,
[tex]V_1 = \dfrac {4}{3}\times 3.14\times (4)^3[/tex]
[tex]V_1 = 267.94 \;\rm cm^3[/tex]
For the outer radius, the volume is given as,
[tex]V_2= \dfrac {4}{3}\times 3.14\times (6)^3[/tex]
[tex]V_2 = 904.32\;\rm cm^3[/tex]
The final volume of the ball is the difference between the volume of the inner and outer surface.
[tex]V = V_2 - V_1[/tex]
[tex]V = 904.32- 267.94[/tex]
[tex]V = 636.38 \;\rm cm^3[/tex]
Hence we can conclude that the volume of the ball is 636.38 cm^3. Option C shows the correct volume of the ball.
To know more about the volume, follow the link given below.
https://brainly.com/question/1578538.