someone help please:

find the value of x

2x - 2 = 4x + 6

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manikakhadka267 manikakhadka267 · Answer 1 · 2022-02-22T15:24:26+01:00

Answer:

or, 2x=4x+8

or, -2x=8

or, x=-4

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ThαtButtєřflíєs ThαtButtєřflíєs · Answer 2 · 2022-02-22T15:40:08+01:00

Given Equation :-

[tex]\qquad[/tex][tex] \pink{\bf \longrightarrow 2x -2 = 4x +6} [/tex]

Let's overturn the equation –

[tex]\qquad[/tex][tex] \sf \longrightarrow 4x +6 = 2x -2 [/tex]

Subtract 2x from both side –

[tex]\qquad[/tex][tex] \sf \longrightarrow 4 x +6 -2x = 2x -2 -2x[/tex]

Cancel 2x from right side & also simplify this equation

[tex]\qquad[/tex][tex] \sf \longrightarrow 4 x +6 -2x =\cancel{ 2x} -2 -\cancel{2x}[/tex]

[tex]\qquad[/tex][tex] \sf \longrightarrow 2x +6 = -2 [/tex]

Now, subtract 6 from both side

[tex]\qquad[/tex][tex] \sf \longrightarrow 2x +6 -6 = -2-6[/tex]

Once again, cancel 6 from left side –

[tex]\qquad[/tex][tex] \sf \longrightarrow 2x +\cancel{6} -\cancel{6} = -2-6[/tex]

On simplification –

[tex]\qquad[/tex][tex] \sf \longrightarrow 2x = -8[/tex]

Now, divide both sides by 2

[tex]\qquad[/tex][tex] \sf \longrightarrow \dfrac{2x}{2} = \dfrac{-8}{2}[/tex]

[tex]\qquad[/tex][tex] \sf \longrightarrow \dfrac{\cancel{2}x}{\cancel{2}} =\cancel{ \dfrac{-8}{2}}[/tex]

[tex]\qquad[/tex][tex] \pink{\bf \longrightarrow x = -4} [/tex]