Respuesta :

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[tex]9y^2-12y-14=0\\D=(-12)^2-4\times9\times(-14)=144+504=648=(\pm18\sqrt{2})^2 \\\\y_1=\dfrac{12+18\sqrt{2} }{18} =\dfrac{2+3\sqrt{2} }{3} \\\\y_2=\dfrac{12-18\sqrt{2} }{18} =\dfrac{2-3\sqrt{2} }{3}[/tex]

Answer:

Solve the equation for y by finding a,b, and c of the quadratic then applying the quadratic formula.

Desimal Form:  2.08088022…,−0.74754689…

the guy on top of me is right I just gave you the desimal form he/she give you the rest

Step-by-step explanation:

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