Suppose that X stands for a temperature in degrees Celsium, Y the same temperature in degrees Fahrenheit. So: Y = (9/5)*X + 32


Let E(X)=10 and Var(X)=2, Find E(Y) and Var(Y).

Respuesta :

The value of E(Y) and Var(Y) are 50 and 178/5 respectively

Temperatures measurement

Given the formula for temperature conversion expressed as:

Y = (9/5)*X + 32

where:

X stands for a temperature in degrees Celsius,

Y the same temperature in degrees

If E(X) = 10, then;

Y = (9/5) * 10 + 32

Y = (9*2) + 32

Y = 18 + 32

Y = 50

Hence E(Y) = 50

If Var(X) = 2

Y = (9/5) * 2 + 32

Y = 18/5 + 32

Y =  178/5

Hence Var(Y) = 50

The value of E(Y) and Var(Y) are 50 and 178/5 respectively

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