Respuesta :
The reaction is a second order reaction, the rate with respect to F2 is 40 * 10 ^-4 torr/min and the molecular geometry is square planar.
The Rate of Reaction
Rate of Reaction;
rate = k[D]^a [f2]^b
The coefficient of DFu = 1
The rate of reaction = - rate of DFu
Let's add the values of trial (i) and (ii) and dividing (i) by (ii)
[tex]\frac{5.0*10^-^3}{10.0*10^-^3} = \frac{k[1500]^a[1500]^b}{k[3000]^a[1500]^b} \\\frac{1}{2} = [\frac{1}{2}] ^a\\a = 1 ...eq(i)[/tex]
similarly for trial (i) and (iii)
[tex]\frac{5*10^-^3}{20*10^-^3}= \frac{k[1500]^a[1500]^b}{k[1500]^a[3000]^b} \\ \frac{1}{4} = [\frac{1}{2}]^b\\ b = 2 ...eq(ii)[/tex]
The rate of the reaction is
[tex]Rate = k[D]{F_2]\\[/tex]
a).
I will disagree because from rate equation above, it is a second order with respect to F2.
b).
As the rate of reaction or rate of formation of FDu in trial (iii) is
[tex]20*10^-^4[/tex]
From equation of reaction
[tex]D + 2f_2 \to DFu[/tex]
The rate with respect to F2
[tex]2 * 20 * 10^-^4 = 40 * 10 ^-^4 torr/min[/tex]
c).
DFu
D has 8 valance electrons which is group 18
This would mean that D has 4 bonds pair and 2 lone pair. This is at
[tex]AB_uX_2[/tex]
x = lone pair
The molecular geometry = square planar
Which is i agree to this.
The reaction is a second order reaction, the rate with respect to F2 is 40 * 10 ^-4 torr/min and the molecular geometry is square planar.
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