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An object weighing 120 n is set on a rigid beam of negligible mass at a distance of 3 m from a pivot, as shown above. A vertical force is to be applied to the other end of the beam a distance of 4 m from the pivot to keep the beam at rest and horizontal. What is the magnitude f of the force required?.

Respuesta :

asuwafohjames

The force required to keep the beam in equilibrium is 90 N.

Principle of moments of forces

It states that for a system at equilibrium, the sum of the clock-wise moment is equal to the sum of anti clock wise moment.

To calculate the magnitude of the force required to keep the beam at equilibrium, we use the Formula below.

Formula:

  • Fd = fD............... Equation 1

Where

  • F = Force/ weight of the object
  • d = Distance of the object from the pivot
  • f = Vertical force applied on the other end
  • D = Distance of the vertical force from the pivot.

Make f the subject of the equation

  • f = Fd/D............... Equation 2

From the question,

Given:

  • F = 120 N
  • d = 3 m
  • D = 4 m

Substitute the given values into equation 2

  • f = (120×3)/4
  • f = 90 N

Hence, The force required to keep the beam in equilibrium is 90 N.

Learn more about moments of forces here: https://brainly.com/question/14303536


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