Line AB passes through (-3,5) and (p, -7), and line CD passes through (3,-1) and (-4,5). For what
value of p, the lines AB and CD are parallel to each other?
Please help me ASPA I NEED THIS BY EVENING

Respuesta :

Answer:

p = 11

Step-by-step explanation:

Let's start by finding the slope of line CD:

[tex]Slope=\frac{y_2-y_1}{x_2-x_1}[/tex]

Plug in the given coordinates into the equation:

[tex]Slope=\frac{5-(-1)}{-4-3}=\frac{5+1}{-7}=-\frac{6}{7}[/tex]

Parallel lines have the same slope. This means we can plug the slope of line CD in to find p (in this case p is [tex]x_2[/tex])...

[tex]Slope=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]-\frac{6}{7}=\frac{-7-5}{p-(-3)}\\-\frac{6}{7}=\frac{-12}{p+3}[/tex]

Cross multiply (multiply numerator of first fraction by denominator of second and vice versa):

[tex]6(p+3)=(-7)(-12)[/tex]

Distribute:

[tex]6p+18=84[/tex]

Subtract 18 from both sides:

[tex]6p=66[/tex]

Divide both sides by 6

[tex]p=11[/tex]