Oklol376
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the area of a triangle is 6 and 3/8 square yards. The height of the triangle is 2 and 1/2 yards. What is the length of the base of the triangle? pls help this is a important question

Respuesta :

Solution:

Note that:

  • Area of triangle = 6 3/8 yd²
  • Height of triangle = 2 1/2
  • Area of triangle = 1/2 x base x altitude

Use the formula to find the base of the triangle.

  • 1/2 x base x altitude = 6 3/8 yd²
  • => 1/2 x base x 2 1/2 = 6 3/8 yd²
  • => 1/2 x base x 5/2 = 6 3/8 yd²
  • => 5/4 x base = 6 3/8 yd²
  • => base = 6 3/8 ÷ 5/4 yd
  • => base = 51/8 x 4/5 yd
  • => base = 51/2 x 1/5 yd
  • => base = 51/10 yd

The length of the base is 51/10 yards.

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  • Area of triangle = 6 3/8 yards²
  • Height of triangle = 2 1/2 yards

[tex]\large{|\underline{\mathtt{\red{T}\blue{o}\orange{\:}\pink{F}\blue{i}\purple{n}\green{d}\red{↯}\blue{}\orange{}}}}[/tex]

  • Base of triangle = ?

[tex]\large\underline{\underline{\maltese{\blue{\pmb{\sf{\: Explanation :-}}}}}}[/tex]

[tex] \boxed{\mathfrak{area = \frac{1}{2} \times base \times height}}[/tex]

We are already given the values, Let's plug them and solve for x i.e base

[tex] \bf\: 6 \frac{3}{8} = \frac{1}{ \cancel2} \times x \times \cancel2 \frac{1}{2} [/tex]

[tex] \bf \: 6\frac{3}{8} = x \times \frac{1}{2} [/tex]

Convert the mixed number to an improper fraction

[tex] \bf \: \frac{51}{8} = \frac{1}{2} x[/tex]

Multiply both sides of the equation by 2

[tex] \boxed{ \tt \: x = \frac{51}{4} }[/tex]

➪ Therefore, The base of the triangle is 51/4 yards...~

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