PLEASEEEEE HELPPP
I need help for numbers 22, 24, 26, 28, 30, 32, 34, 36

Answer:
Step-by-step explanation:
use SOH CAH TOA to remember sin cos and tan functions
Sin = oppostive/hypotenuse
Cos = adjacent/hypotenuse
Tan = opposite/adjacent
22. cos(x) = b/c
24. sin(x) = 2/2sqrt(17) = 1/sqrt(17)
26. tan(x) = 2/8 = 1/4
28. cos(y) = 2/2sqrt(17) = 1/sqrt(17)
30. sin(30)
in a 30 60 90 triangle, the side opposite 30 is 1, the side opposite 60 is sqrt(3), the side opposite 90 is 2.
sin(30) = opposite/hypotenuse = 1/2/1 = 1/2
32.
in a 45 45 90 triangle, the side opposite 45 is 1, the side opposite 45 is 1, the side opposite 90 is sqrt2.
sin = opposite/hypotenuse = 1/sqrt(2)
34. cos(30) = sqrt(3)/2
36. tan(31) = AC/9 --> AC = 9tan(31) = 5.408
Answer:
22. [tex]\dfrac{b}{c}[/tex]
24. [tex]\dfrac{\sqrt{17} }{17}[/tex]
26. [tex]\dfrac14[/tex]
28. [tex]\dfrac{\sqrt{17} }{17}[/tex]
30. [tex]\dfrac12[/tex]
32. [tex]\dfrac{\sqrt{2} }{2}[/tex]
34. [tex]\dfrac{\sqrt{3} }{2}[/tex]
36. AC = 5.41 (nearest hundredth)
Step-by-step explanation:
Using trig ratios:
[tex]sin(\theta)=\dfrac{O}{H}\\\\\\cos(\theta)=\dfrac{A}{H}\\\\\\tan(\theta)=\dfrac{O}{A}[/tex]
where [tex]\theta[/tex] is the angle, O is the side opposite the angle, A is the side adjacent the angle, H is the hypotenuse of a right angle
22. [tex]cos(x)=\dfrac{b}{c}[/tex]
24. [tex]sin(x)=\dfrac{2}{2\sqrt{17} }=\dfrac{\sqrt{17} }{17}[/tex]
26. [tex]tan(x)=\dfrac{2}{8}=\dfrac14[/tex]
28. [tex]cos(y)=\dfrac{2}{2\sqrt{17} }=\dfrac{\sqrt{17} }{17}\dfrac{}{}[/tex]
30. [tex]sin(30)=\dfrac12[/tex]
32. [tex]sin(45)=\dfrac{\sqrt{2} }{2}[/tex]
34. [tex]cos(30)=\dfrac{\sqrt{3} }{2}[/tex]
36. [tex]tan(31)=\dfrac{AC}{9}[/tex]
[tex]\implies AC=9tan(31)=5.41[/tex] (nearest hundredth)