Answer:
As per Given Information
Angle on which the stone thrown ,theta = 45°
Velocity ,u = 10m/s
Acceleration due to gravity ,g is 10m/s²
We have to find the "Range of Projectile "
Range of projectile is denoted by R .
Using Formulae
[tex]\\ \bigstar{\boxed{\pink{\bf{R = \frac{ {u}^{2}sin2 \theta }{g} }}}} \\ \\ [/tex]
On putting the value we get
[tex] \sf\dashrightarrow \: R\: = \frac{ {10}^{2} \times sin(2 \times 45) }{10} \\ \\ \sf\dashrightarrow \: R = \frac{100 \times sin90 {}^{ \circ} } {10} \\ \\ \sf\dashrightarrow \: R \: = \frac{100 \times 1}{10} \\ \\ \sf\dashrightarrow \: R \: = \frac{100}{10} \\ \\ \sf\dashrightarrow \: R = \cancel \frac{100}{10} \\ \\ \sf\dashrightarrow \: R = 10m[/tex]
So, the range of projectile is 10m.
