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Assume that a 19-cm length of wire is carrying a current perpendicular to a 4.1-T magnetic field and experiences a force of 7.6 mN. What is the current in the wire?

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asuwafohjames

The current in the wire is 0.00975 A.

What is electric current?

Elecric current is the rate of flow of charge in a circuit.

To calculate the current in the wire, we use the formula below.

Formula:

  • F = BILsin∅............... Equation 1

Where:

  • F = Force
  • B = Magnetic field
  • I = Current in the wire
  • L = Length of the wire
  • ∅ = Angle between the wire and the field

make I the subject of the equation

  • I = F/BLsin∅........... Equation 2

Given:

  • F = 7.6 mN = 0.0076 N
  • B = 4.1 T
  • L = 19 cm = 0.19 m
  • ∅ = 90° (perpendicular)

Substitute the given values into equation 2

  • I = (0.0076)/(4.1×0.19×sin90°)
  • I = 0.0076/0.779
  • I = 0.00975 A

Hence, The current in the wire is 0.00975 A.

Learn more about electric current here: https://brainly.com/question/14883923


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