Answer:
141.0g of H2SO4
Explanation:
2 mole of NaOH reacts with 1 mole of H2SO4 completely
NaOH = 23 + 16 + 1 = 40g/mol
2 mole = 40g/mol x 2 mol = 80g
H2SO4 = 2(1) + 32 + 4(16) = 98g/mol
1 mole = 98g/mol x 1 mol = 98g
80g reacts with 98g completely
80g ------------ 98g
115g ------------ x
80x = 115 x 98
80x = 11270
x = 11270/80
x = 140.875g
x is approximately 141g
Therefore 115g of NaOH will react completely with 141g of H2SO4
