2.87mL of 2.5 M K2SO4 are required to obtain 1.25 grams of the compound.
The volume of a substance can be calculated by dividing the number of moles of the substance by its molarity. That is;
volume = no. of moles ÷ molarity
According to this question, 2.5M K2SO4 are required to obtain 1.25 grams of the compound. The volume can be calculated as follows:
Molar mass of K2SO4 = 174.26 g/mol
moles of K2SO4 = 1.25g ÷ 174.26g/mol
moles of K2SO4 = 0.00717moles
Volume = 0.00717moles ÷ 2.5
Volume = 0.00287 L = 2.87mL.
Therefore, 2.87mL of 2.5 M K2SO4 are required to obtain 1.25 grams of the compound.
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