PLEASE PLEASE HELP
PLEASE HELP PLEASE HELP

The center of the hanger represents an equal sign, since both sides of the hanger are equal.
Given different coloured triangles and shapes, we can assign a variable to each of them.
Let one green triangle be equal to [tex]a[/tex].
Let one blue square be equal to [tex]b[/tex]
Let one red circle be equal to [tex]c[/tex].
Let one yellow pentagon be equal to [tex]d[/tex].
On the left side of the hanger/equation, there are 3 green triangles. This means that one of our terms in our equation will be [tex]3a[/tex].
Under the triangles on the left side is 1 blue square. This means that the next term could be [tex]1b[/tex], or just [tex]b[/tex].
Next is 2 red circles ⇒ [tex]2c[/tex]
And finally are 3 yellow pentagons ⇒ [tex]3d[/tex]
To sum up the left side as an expression, we can write all the terms we have just written as a sum:
[tex]3a+b+2c+3d[/tex]
Now, after doing the same procedure for the right side of the hanger, we get:
[tex]2a+3b+c+2d[/tex]
For now, we only have two expressions representing the two sides of the hanger:
Left: [tex]3a+b+2c+3d[/tex]
Right: [tex]2a+3b+c+2d[/tex]
To turn these into an equation, we must have an equal sign.
Remember that both sides of the hanger are equal. Knowing this, we can state the following:
Left side = Right side
[tex]3a+b+2c+3d = 2a+3b+c+2d[/tex]
[tex]3a+b+2c+3d = 2a+3b+c+2d[/tex]