Answer:
see below
Step-by-step explanation:
Set the equation equal to 0
[tex]2x^{2} -5x+3[/tex]
a = 2
b = -5
c = 3
plug values in to quadratic formula
[tex]x=\frac{-b+/-\sqrt{b^{2} -4ac} }{2a}[/tex]
[tex]x=\frac{-(-5)+/-\sqrt{(-5)^{2} -4(2)(3)} }{2(2)}[/tex]
simplify
[tex]x=\frac{5+/-\sqrt{25 -24} }{4}[/tex]
[tex]x=\frac{5+/-\sqrt{1} }{4}[/tex]
[tex]\sqrt{1} = 1[/tex]
we get two options
[tex]x=\frac{5+1 }{4}[/tex]
[tex]x=\frac{6 }{4}[/tex]
and
[tex]x=\frac{5-1 }{4}[/tex]
[tex]x=\frac{4 }{4} = 1[/tex]
