In a certain population of mice, a single gene controls fur color. There are two possible alleles: B, which leads to a black fur, and W, which leads to white fur. Individuals with the genotype BB will have a black fur, individuals with the genotype WW will have white fur, and individuals with the genotype BW will have gray fur. Scientists recorded the fur color of 1,000 mice from the population. They found that 200 mice have black fur, 400 have gray fur, and 400 have white fur. Ten years later, the measurements are repeated. Again, they recorded the fur color of 1,000 mice. They found that 400 have black fur, 400 have gray fur, and 200 have white fur.

Part A: Show the Hardy-Weinberg calculations for the beginning and ending populations. Include the values for the equation as well as the p and q values. Show your work.

Part B: Use the Hardy-Weinberg calculation to explain if this population is evolving or not. Then propose a hypothesis about the environment of these mice that would lead to these observations.

Respuesta :

The Hardy-Weinberg calculations for the beginning and ending populations is mathematically given as

  • p2+q2+2pq = 1
  • p2+q2+2pq = 1
  • I presume this to be caused by environmental conditions that  affects black fur color

Hardy-Weinberg calculation to explain population

Beginning

Black = BB = 200

-Frequency, p2 = 0.2

Gray = BW = 400

-Frequency, 2pq = 0.4

White = WW = 400

-Frequency, q2 = 0.4

Therefore, Frequency of p

[tex]Fp = \frac{(400+400}{2000}[/tex]

Fp = 0.4

Frequency of q

Fq= (400+800)/2000

Fq = 0.6

Hence

p+q = 1

p2+q2+2pq = 1

End,

Black =400

-Frequency, p2 = 0.4

Gray =400

-Frequency, 2pq = 0.4

White = 200

-Frequency, q2 = 0.2

Frequency of p

Fp'= (800+400)/2000

Fp'= 0.6

Frequency of q

Fq'= (400+400)/2000

Fq' = 0.4

p+q = 1

p2+q2+2pq = 1

Therefore, we can see that the  population is under H-W equilibrium.

We also see an increased frequency of black fur. I presume this to be caused by environmental conditions that  affects black fur color.

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