The area of the shape with parallel sides is 28 unit².
A trapezoid is a quadrilateral (has four sides and four angles) with two pairs of parallel sides. The area is given by:
A = (1/2) * (a + b)h
Where a, b is the length of the parallel sides and h is the height of the trapezoid.
Given that a = 8, b = 6 and h = 4, hence:
A = (1/2) * (8 + 6) * 4 = 28 unit²
The area of the shape with parallel sides is 28 unit².
Find out more on Trapezoid at: https://brainly.com/question/1410008
Answer:
28
Step-by-step explanation:
khan
Strategy
Area tells us the amount of space enclosed by the figure.
There are many ways we could split up the space into simpler shapes. Let's split the figure into two triangles.
We can find the area of each triangle, then add them to find the total area.
Hint #22 / 5
Area of the triangle on the left
The triangles have the same height.
\begin{aligned} \text{Area}_\text{triangle} &= \dfrac{1}{2} \cdot \text{base} \cdot \text{height}\\\\ &= \dfrac{1}{2} \cdot 6 \cdot 4\\\\ &= 12 \end{aligned}
Area
triangle
=
2
1
⋅base⋅height
=
2
1
⋅6⋅4
=12
The triangle on the left has an area of \blueE{12}12start color #0c7f99, 12, end color #0c7f99 square units.
Hint #33 / 5
Area of the triangle on the right
\begin{aligned} \text{Area}_\text{triangle} &= \dfrac{1}{2} \cdot \text{base} \cdot \text{height}\\\\ &= \dfrac{1}{2} \cdot 8 \cdot 4\\\\ &= 16 \end{aligned}
Area
triangle
=
2
1
⋅base⋅height
=
2
1
⋅8⋅4
=16
The triangle on the right has an area of \maroonD{16}16start color #ca337c, 16, end color #ca337c square units.
Hint #44 / 5
Total area
To find the total area of the shape, we can add the two partial areas.
\blueE{12}+\maroonD{16}=\purpleD{28}12+16=28start color #0c7f99, 12, end color #0c7f99, plus, start color #ca337c, 16, end color #ca337c, equals, start color #7854ab, 28, end color #7854ab
Hint #55 / 5
The area of the shape is 28 \text{ units}^228 units
2
28, start text, space, u, n, i, t, s, end text, squared.
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