This problem is providing the mass of aspartame as 10 g and asks for the moles in such amount. At the end, after applying a mole-mass proportional factor, the answer turns out to be 0.03 mol.
In chemistry, mole-mass relationships are mathematical procedures we use in order to calculate grams from moles or vice versa, according to a given requirement.
In such a way, when given 10 g of aspartame and required to calculate moles, we first need to calculate its molar mass as follows:
[tex]MM=14*12.01+18*1.01+2*14.01+5*16.0\\\\MM=294.29g/mol[/tex]
Then, we apply the following proportional factor cancelling out the grams and leading to moles:
[tex]10g*\frac{1mol}{294.29g} =0.03mol[/tex]
Which has one significant figure as well as the initial 10 g.
Learn more about mass and moles: https://brainly.com/question/11915867
