Respuesta :
Answer:
Explanation:
The molar volume of a gas at STP (Standard Temperature and Pressure), which is equal to 22.4 liters.
There are 6.02x10^23 molecules in 1 mole of Argon.
So for 1.51x10^24 molecules of Argon, the volume at STP should be
(1.51x10^24 / (6.02x10^23)) * 22.4
= 56.19 liters
Moles of Argon:-
- No of molecules/Avagadro's constant
- 1.51×10^24/6.022×10^23=2.5mol
Now
- 1mol of gas contains 22.4L
- 2.5mol contains:-
[tex]\\ \rm\Rrightarrow 2.5(22.4)=56L[/tex]
