PLEASE HELP!!!! The focus of a parabola is (βˆ’6,βˆ’3) . The directrix of the parabola is y=4.
What is the equation of the parabola?



y=βˆ’1/28(x+6)^2+1/2


y=βˆ’1/28(xβˆ’1/2)^2βˆ’6


y=βˆ’1/14(x+1/2)^2+6


y=βˆ’1/14(x+6)^2+1/2


The directrix of a parabola is y=βˆ’4. The focus of the parabola is (βˆ’2,βˆ’2) .


What is the equation of the parabola?



y=βˆ’1/4(xβˆ’2)^2βˆ’3


y=1/4(x+2)^2βˆ’3


y=βˆ’1/8(x+2)^2+3


y=1/8(xβˆ’2)^2βˆ’3


The directrix of a parabola is y=9. The focus of the parabola is (2,5).


What is the equation of the parabola?



y=βˆ’1/8(xβˆ’2)^2+7


y=1/8(xβˆ’2)^2βˆ’7


y=βˆ’1/8(xβˆ’2)^2βˆ’7


y=1/8(xβˆ’2)^2+7

PLEASE HELP The focus of a parabola is 63 The directrix of the parabola is y4 What is the equation of the parabola y128x6212 y128x1226 y114x1226 y114x6212 The d class=
PLEASE HELP The focus of a parabola is 63 The directrix of the parabola is y4 What is the equation of the parabola y128x6212 y128x1226 y114x1226 y114x6212 The d class=
PLEASE HELP The focus of a parabola is 63 The directrix of the parabola is y4 What is the equation of the parabola y128x6212 y128x1226 y114x1226 y114x6212 The d class=