Respuesta :

The measure of line segment BC is; 10cm

The angle measure m∠bcd is; 120°

The measure of line segment AB is; 5 cm

The measure of line segment BE is; 4.33 cm

Line segments and angle measures in a parallelogram

By convention, for parallelograms, the length of its opposite sides are equal, it follows that;

  • AB = CD = 5cm and

  • AD = BC

Additionally, the measure of the adjacent angles is supplementary;

m∠C + m∠D = 180

On this note, it follows that, m<BCD = 120°, since m∠D is; 60° from the diagram

From the sine rule of triangle sides and angles; the measure of line segment BE can be evaluated as follows;

  • BD/sin 120 = CD/sin 30

  • BD/sin120 = 2(5)

  • BD = 10sin120

BD = 8.66

Hence, since BD = 2BE holds from the diagram;

  • BE = BD/2

  • BE = 8.66/2

BE = 4.3

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Answer:

BC= 10

BCD= 120

AB= 5

EB= 6.1

Explanation:

I did it

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