Using the relation between velocity distance and time, it is found that his second practice was 0.66 km/h faster than his first.
Velocity is distance divided by time, hence:
[tex]v = \frac{d}{t}[/tex]
On his first practice, he ran a distance of 10 km in 1:01:49, that is, 1 hour plus 109 seconds, which considering that an hour has 3600 seconds, is a time of:
[tex]t = 1 + \frac{109}{3600} = 1.0303[/tex]
Hence, the velocity in km/h is:
[tex]v_1 = \frac{10}{1.0303} = 9.71[/tex]
On the second practice, the time was of 57:53, hence:
[tex]t = \frac{57 \times 60 + 53}{3600} = 0.96472222222[/tex]
[tex]v_2 = \frac{10}{0.96472222222} = 10.37[/tex]
10.37 - 9.71 = 0.66.
His second practice was 0.66 km/h faster than his first.
More can be learned about the relation between velocity distance and time at https://brainly.com/question/24316569
