If a car changes velocity from 36 m/s to 28 m/s with an
acceleration of -2.0 m/s2, then how much time does it take for
the vehicle to slow down?
Need answer asap

If a car changes velocity from 36 ms to 28 ms with an acceleration of 20 ms2 then how much time does it take for the vehicle to slow down Need answer asap class=

Respuesta :

  • Initial velocity=36m/s=u
  • Final velocity=v=28m/s
  • Acceleration=a=-2m/s^2
  • Time=t

[tex]\\ \rm\bullet\rightarrowtail v=u+at[/tex]

[tex]\\ \rm\bullet\rightarrowtail 28=36-2t[/tex]

[tex]\\ \rm\bullet\rightarrowtail -2t=-8[/tex]

[tex]\\ \rm\bullet\rightarrowtail t=4s[/tex]

Given :

Initial velocity= [tex]36m/s=u[/tex]

Final velocity= [tex]v=28m/s[/tex]

Acceleration= [tex]a= -2m/s²[/tex]

Lets, time be [tex]t[/tex]

[tex]→ v = u + at[/tex]

[tex]→ 28 = 36 - 2t[/tex]

[tex]→ -2t = -8[/tex]

[tex]→ t = 4s[/tex]