☆Given :
[tex] \\ [/tex]
[tex] \\ [/tex]
☆To find :
[tex] \\ [/tex]
[tex] \\ [/tex]
☆Solution:
[tex] \\ [/tex]
So to find perimeter of triangle first we have to find value of x.
[tex] \\ [/tex]
As it's Given one angle is 90°
So we can find value of x by using this formula:-
[tex] \\ [/tex]
Hypotenuse ² = Base² + perpendicular ²
[tex] \\ [/tex]
Where :-
Hypotenuse is AC
Base is BC
Perpendicular is AB
[tex] \\ [/tex]
So:-
[tex] \\ [/tex]
⇢AC² = BC² + AB²
[tex] \\ [/tex]
⇢8² = 5² + x²
[tex] \\ [/tex]
⇢64 = 5² + x²
[tex] \\ [/tex]
⇢64 = 25 + x²
[tex] \\ [/tex]
⇢25 + x² = 64
[tex] \\ [/tex]
⇢x² = 64 - 25
[tex] \\ [/tex]
⇢x² = 39 in.
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⇢x = √(39)
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⇢x = 6.2
[tex] \\ [/tex]
Now Let's find perimeter of triangle.
We know :-
Perimeter of triangle = Side one + side two + side 3
[tex] \\ [/tex]
So:-
[tex] \\ [/tex]
⇢Perimeter of triangle = AB + BC + AC
[tex] \\ [/tex]
⇢Perimeter of triangle = 5 + 8 + 6.2
[tex] \\ [/tex]
⇢Perimeter of triangle = 13 + 6.2
[tex] \\ [/tex]
⇢Perimeter of triangle = 19.2 in.
