Find the equation (in terms of x ) of the line through the points (-5,1) and (4,0)

Answer:
[tex]y = -\frac{1}{9}x+\frac{4}{9}[/tex]
Step-by-step explanation:
y = mx + b
First, we need to find the slope using (-5,1) and (4,0):
[tex]\frac{y_2-y_1}{x_2-x_1}[/tex] = [tex]\frac{0-1}{4-(-5)}[/tex] = [tex]\frac{0-1}{4+5}[/tex] = [tex]\frac{-1}{9}[/tex] = [tex]-\frac{1}{9}[/tex]
(-5,1)
y = [tex]-\frac{1}{9}[/tex]x + b
1 = [tex]-\frac{1}{9}(-5)[/tex] + b
1 = [tex]\frac{5}{9}[/tex] + b
9(1 = [tex]\frac{5}{9}[/tex] + b)
9 = 5 + 9b
-5 -5
4 = 9b
/9 /4
[tex]\frac{4}{9}[/tex] = b
[tex]y = -\frac{1}{9}x+\frac{4}{9}[/tex]
View attached graph to check our answer :)
Hope this helps!