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PLS HELP!!!! is the the relationship between the values in each table a direct variation, an inverse variation, or neither? Write equations to model the direct and inverse variations. Suppose that x and y vary inversely. write a function that models each inverse variation. Graph the function and find y when x=10. each ordered pair is from an inverse variation. Find the constant of variation.

PLS HELP is the the relationship between the values in each table a direct variation an inverse variation or neither Write equations to model the direct and inv class=

Respuesta :

The value of the product and the ratio of the variables is a constant in an

inverse and direct variation respectively.

Responses:

  1. Inverse variation
  2. Neither
  3. Direct variation
  4. Direct variation
  5. Neither
  6. Inverse variation
  7. Please find attached the required graph; when x = 10, y = 1.4
  8. The graph is attached; when x = 10, y = 0.08
  9. When x = 10, y = 0.03
  11. [tex]The \ function \ that \ models \ the \ data \ is; \, h = \dfrac{360}{p}[/tex]
  12. 48 hats
  13. 1
  14. 1.2
  15. 50
  16. [tex]\dfrac{2}{7}[/tex]
  17. -286
  18. 5
  19. [tex]\dfrac{2}{7}[/tex]
  20. 13.92
  21. [tex]-\dfrac{1}{4}[/tex]
  22. 19

Which methods can be used to find the relationship between the variables?

1. y·x is a constant, therefore, the relationship is an inverse variation

2. Neither y·x or [tex]\dfrac{y}{x}[/tex] is constant, therefore, the relationship is neither direct or inverse variation

3. [tex]\mathbf{\dfrac{y}{x}}[/tex] is constant, therefore, the relationship is a direct variation

4. [tex]\dfrac{y}{x}[/tex] is constant, therefore, the relationship is a direct variation

5. Neither y·x or [tex]\dfrac{y}{x}[/tex] is constant, therefore, the relationship is neither direct or inverse variation

6. y·x is a constant, therefore, the relationship is an inverse variation

7. C = 7 × 2 = 14

The function is therefore;

  • [tex]\underline{y = \dfrac{14}{x}}[/tex]

When x = 10, we have;

  • [tex]y = \dfrac{14}{10} = \underline{1.4}[/tex]

8. C = 0.2 × 4 = 0.8

The function is therefore;

  • [tex]\underline{y = \dfrac{0.8}{x}}[/tex]

When x = 10, we have;

[tex]y = \dfrac{0.8}{10} = \underline{0.08}[/tex]

9. C = [tex]\frac{9}{10} \times \frac{1}{3} = \frac{3}{10}[/tex] = 0.3

The function is therefore;

  • [tex]\underline{y = \dfrac{0.3}{x}}[/tex]

When x = 10, we have;

  • [tex]y = \dfrac{0.3}{10} = \underline{0.03}[/tex]

Please find attached the required graphs created with MS Excel

10. a. From the given table, we have;

C = p × h = 360 (constant)

Which gives;

  • [tex]The \ function \ that \ models \ the \ data \ is; \, \underline{h = \dfrac{360}{p}}[/tex]

b. If they charge p = $7.50 per hat, we have;

  • [tex]Number \ of \ hats \ they \ should \ expect \ to \ sell \ is; \, h = \dfrac{360}{7.50} = \underline{48}[/tex]

13. The constant is the product of the ordered pair;

[tex]C = 3 \times \dfrac{1}{3} =\underline{ 1}[/tex]

14. The constant, C = 0.6 × 6 = 1.2

15. The constant C = 10 × 5 = 50

16. C = [tex]\dfrac{5}{7} \times \dfrac{2}{5}[/tex] = [tex]\underline{\dfrac{2}{7}}[/tex]

17. C = -13 × 22 = -286

18. [tex]C = \dfrac{1}{2} \times 10[/tex] = 5

19. C = [tex]\dfrac{1}{3} \times \dfrac{6}{7}[/tex] = [tex]\underline{\dfrac{2}{7}}[/tex]

20. C = 4.8 × 2.9 = 13.92

21. C = [tex]\dfrac{5}{8} \times -\dfrac{2}{5}[/tex] = [tex]\underline{-\dfrac{1}{4}}[/tex]

22. 4.75 × 4 = 19

Learn more about direct and inverse relationship here:

https://brainly.com/question/4386945

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