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 Jalen is painting her great room including the ceiling but not the floor. The room measures 20 ft long, 30 wide and 9 ft tall. If each paint container covers 400 sq ft, how many cans should she buy? PLEASE HELPP MEEEE asap

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fieryanswererft

4 cans of paint

[tex]\sf ---> \ \ {\boxed {\boxed {\frac{area \ of \ room - area \ of \ floor}{area \ the \ paint \ covers} }}}[/tex]

[tex]\hookrightarrow \sf {\dfrac{2(wl+hl+hw)- (lw)}{400}}[/tex]

[tex]\hookrightarrow \sf {\dfrac{2((30)(20)+(9)(20)+(9)(30))-(20*30)}{400}[/tex]

[tex]\hookrightarrow \sf {\dfrac{1500}{400}[/tex]

[tex]\hookrightarrow \rm {\sf {3.75}}[/tex]

→ She should buy max 4 cans as she cannot buy 3.75 cans.

Here l refers to length, w refers to width, h refers to height.

Area to be painted = Area of walls + Area of ceiling

= 2(hl+hb)+lb

Where,

  • H is height
  • L is length
  • B is breadth or width

In our case,

  • H = 9 ft
  • L = 20 ft
  • B = 30 ft

Put the values in the formula ~

= 2(9×20+9×30)+20×30

= 2(180+270)+600

= 2×450+600

= 900+600

= 1500 ft²

Now,

Required number of cans = 1500/400 = 3.75

  • round it off to 4

➪ Thus, she needs to buy 4 cans of paint...~

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