Three equal in magnitude charges are located at the corners of an equilateral
triangle of side r. The charges A and C are positive and charge B is negative.

What is the direction of the net force on charge C due to charges A and B?

(A) up to the right

(B) up

(C) right

(D) down

Three equal in magnitude charges are located at the corners of an equilateral triangle of side r The charges A and C are positive and charge B is negative What class=

Respuesta :

The direction of the net force is up.

Net force on the charges

The net force on the charges can be determined using Coulomb's law as follows;

[tex]F_{AC} = + \frac{KQ^2}{r^2}[/tex]

[tex]F_{BC} = - \frac{KQ^2}{r^2}[/tex]

F(net) = F(AC) + F(BC)

F(net) = 0

The, direction of the net force on charge C will be parallel to charge C to achieve a zero net force. Thus, the direction of the net force is up.

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