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For the balanced equation shown below, how many moles of N2 will react with the 0.3034 moles of Mg.
3Mg + N2 --> Mg3N2

**i think it needs to be rounded to the tenth

Respuesta :

Answer:

0.1 moles of N2 will react with 0.3034 moles of Mg.

Explanation:

[tex]\sf{balanced \ eqaution = 3Mg + N2 \rightarrow Mg3N2}[/tex]

  • 0.3034 moles of Mg

using molar ratio:

3Mg : N2

3 : 1

moles of N2:

[tex]\hookrightarrow \sf\frac{0.3034 }{3} *1[/tex]

[tex]\hookrightarrow \sf 0.10113 \ moles \ of \ N2[/tex]