The answer is,
[tex]log_{12}(\frac{1}{4})=\frac{log1/4}{log12}[/tex]
We have given,
[tex]log_{12}(\frac{1}{4})[/tex]
We use the lows of logarithm for an given expression
Which logarithm expression we use here?
[tex]log_{x}(y)[/tex],
Here x is the base and y is the number,
Therefore we have to apply the change of base formula to a logarithmic expression.
So we get,
[tex]\frac{logy}{logx}[/tex]
Here, the base of log is 10
So by using above formula we have,
[tex]log_{12}(\frac{1}{4})=\frac{log1/4}{log12}[/tex]
Therefore we get,
[tex]log_{12}(\frac{1}{4})=\frac{log1/4}{log12}[/tex]
To learn more about logarithm expression visit:
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