The possible energy of the emitted photons of the hydrogen atom in first energy level is -3.41 eV.
Hydrogen atom will emit electrons of certain energy when the hydrogen atom is in excited state.
Let a dot represent first energy level, the possible energy of the emitted photons is calculated as follows;
[tex]E = \frac{R_h}{n^2} \\\\E = \frac{-2.18 \times 10^{-18}}{(2)^2} \\\\E = - 5.45 \times 10^{-19} \ J[/tex]
[tex]E = \frac{-5.45 \times 10^{-19}}{1.6 \times 10^{-19}} \\\\E = -3.41 \ eV[/tex]
Thus, the possible energy of the emitted photons of the hydrogen atom in first energy level is -3.41 eV.
Learn more about energy level of emitted photons here: https://brainly.com/question/11293349
