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Solve the trig equation over the interval [0, 2π).
sin(x) · cos(x) = 0
sin(x) = 0 or cos(x) = 0
From sin(x) = 0, you get
x = 0 or x = π
and from cos(x) = 0
π 3π
x = —— or x = ——
2 2
Solution set: [tex]\mathsf{S=\left\{0,\,\dfrac{\pi}{2},\,\pi,\,\dfrac{3\pi}{2}\right\}.}[/tex]
I hope this helps. =)
