Cassy shoots a large marble (Marble A, mass: 0.06 kg) at a smaller marble (Marble B, mass: 0.03 kg) that is sitting still. Marble A was initially moving at a velocity of 0.7 m/s, but after the collision it has a velocity of −0.2 m/s. What is the resulting velocity of marble B after the collision? Be sure to show your work for solving this problem along with the final answer.

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ThatKidx ThatKidx · Answer 1 · 2022-02-26T05:09:18+01:00

Answer:

We can solve this using the Law of Conservation of Momentum. If both marbles are in our system, the initial momentum should equal the final momentum.

The initial momentum can be solved for as so:

Explanation:

* + =

(0.06)(0.7) + (0.03)(0) = 0.042 [kg * m/s]

So if the system has an initial momentum of 0.042, it should have the same final momentum.

(0.06)(-0.2) + (0.03)() = 0.042

(0.03)() = 0.54

() = 18 [m/s] Hope this helps.

okpalawalter8 okpalawalter8 · Answer 2 · 2022-04-22T12:42:19+02:00

The resulting velocity of marble B after the collision is mathematically given as

v=1.8 m/s

Generally, the equation for the Conservation of linear momentum is mathematically given as

m*v i= m*v f

Therefore

0.06*0.7 + 0.03*0 = 0.06*(-0.2) + 0.03*v

0.06*(0.7+0.2)=0.03*v

v = 0.06*0.9/0.03

v=1.8 m/s

In conclusion, the resulting velocity is

v=1.8 m/s