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How many atoms are in 307 grams of silver (Ag)?
A) 2.85 mol Ag
B) 17.13 atoms Ag
C) 1.71 x 10^24 atoms Ag

Respuesta :

The number of atoms of silver in 307 grams of silver is 1.71 × 10²⁴  atoms

Avogadro's number:

Avogadro's number, number of units in one mole of any substance equals to 6.02214076 × 10²³

Therefore,

1 mole(107.8682 grams) of silver(Ag) = 6.022 × 10²³ atoms

307 grams of Ag = ?

cross multiply

number of atoms of silver =  6.022 × 10²³ × 307 / 107.8682

number of atoms of silver = 1848.754 × 10²³ / 107.8682

number of atoms of silver = 17.1390085308 × 10²³

number of atoms of silver = 1.71 × 10²⁴

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