chandraghimire320
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A metal of mass 25g and dropped into a calorimeter 200g of water initially at 20°C. The final temperature is 22°C. Compute the specific heat of the metal if the water equivalent of calorimeter is 10g.

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Respuesta :

Key words

  • m=mass
  • T=temperature
  • c=Specific heat capacity

[tex]\\ \rm\hookrightarrow Q_{initial}=Q_{Final}[/tex]

[tex]\\ \rm\hookrightarrow m1c1\Delta T=m2c2\Delta T[/tex]

  • Clear ou ∆T

[tex]\\ \rm\hookrightarrow 25c1=(200+10)(1)[/tex]

[tex]\\ \rm\hookrightarrow 25c1=210[/tex]

[tex]\\ \rm\hookrightarrow C1=210/25[/tex]

[tex]\\ \rm\hookrightarrow C1=8.4cal/g°C[/tex]

vijayhalder031

The correct answer is 8.4 J⋅kg−1⋅K−1

Explanation :

  • The mass of the metal and water are  given.
  • The initial temperature and final temperature are given.
  • We need to calculate the Specific heat of metal .

 

We know that

Qi = Qf  

Therefore ,m1c1 ΔT = m2c2ΔT

Where m1 is 25g and m2 is 200g

so , 25c1 = (200+10)(22-2)

      25c1 = 420

Therefore , c1 = 210/25

c1 = 16.8J⋅kg−1⋅K−1

Hence the specific heat of metal is 16.8 J⋅kg−1⋅K−1

Learn more about Specific heat at

https://brainly.in/question/1141811

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