Answer:
D. 5 units
Step-by-step explanation:
To work out the length use formula:
[tex]length = \sqrt{(y₂-y1) {}^{2} + (x₂-x1) {}^{2}} [/tex]
length of AB:
[tex]AB = \sqrt{( - 4 - 5) {}^{2} + ( - 6 - ( - 2)) {}^{2} } = \sqrt{97} [/tex]
length of AC:
[tex]AC = \sqrt{( - 7 - 5) {}^{2} + ( - 2 - ( - 2)) {}^{2} } = 12[/tex]
length of BC:
[tex]BC = \sqrt{( - 7 - ( - 4)) {}^{2} + ( - 2 - ( - 6)) {}^{2} } = 5[/tex]
as you can see BC has the shortest side of 5 units
