The particle diagram shown above represents the dissolution of CuCl(s) assuming an equilibrium concentration for Cu+ ions of about 4×10^-4M in a saturated solution at 25°C. The equilibrium being represented is shown in the following chemical equation.

CuCl(s)⇄Cu+(aq)+Cl−(aq)

Which of the following changes to the particle diagram will best represent the effect of adding 1.0mL of 4MNaCl to the solution?

A. Some of the Cu+ and Cl− ions combine to form CuCl(s) because the Ksp will be lower than 1.6×10−7.
B. Some of the Cu+ and Cl− ions combine to form CuCl(s) because the molar solubility will be lower than 4×10−4M.
C. More Cu+ and Cl− ions will be in solution because the molar solubility will be higher than 4×10−4M.
D. More Cu+ and Cl− ions will be in solution because the Ksp will be higher than 1.6×10−7.

Question

26-02-2022
Chemistry

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The particle diagram shown above represents the dissolution of CuCl(s) assuming an equilibrium concentration for Cu+ ions of about 4×10^-4M in a saturated solution at 25°C. The equilibrium being represented is shown in the following chemical equation.

CuCl(s)⇄Cu+(aq)+Cl−(aq)

Which of the following changes to the particle diagram will best represent the effect of adding 1.0mL of 4MNaCl to the solution?

A. Some of the Cu+ and Cl− ions combine to form CuCl(s) because the Ksp will be lower than 1.6×10−7.
B. Some of the Cu+ and Cl− ions combine to form CuCl(s) because the molar solubility will be lower than 4×10−4M.
C. More Cu+ and Cl− ions will be in solution because the molar solubility will be higher than 4×10−4M.
D. More Cu+ and Cl− ions will be in solution because the Ksp will be higher than 1.6×10−7.

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pstnonsonjoku pstnonsonjoku · Answer 1 · 2022-03-04T10:57:32+01:00

Due to common ion effect, addition of 1.0mL of 4MNaCl will cause some of the Cu+ and Cl− ions combine to form CuCl(s) because the Ksp will be lower than 1.6×10−7.

What is solubility product?

The term solubility product refers to the equilibrium constant that is set up when an ionic substance dissolve in water. Since the solution already contains chloride ions, addition of more chloride ions from NaCl will cause more CuCl(s) to separate from solution.

Hence, when 1.0mL of 4MNaCl is added to the solution, some of the Cu+ and Cl− ions combine to form CuCl(s) because the Ksp will be lower than 1.6×10−7.

Learn more about solubility product: https://brainly.com/question/857770