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Kayla bought a necklace for $15. She also bought some bangle bracelets for $3 each. Kayla spent no more than $30 for the bracelets and the necklace. Which inequality can be used to find b, the number of bangle bracelets that Kayla could have bought?

Respuesta :

fieryanswererft

Answer:

she bought 5 or less than 5 bracelets .

Explanation:

Let bracelets be b,

cost of total bracelets: 3b

inequality:

  • 3b + 15 ≤ 30

  • 3b ≤ 30 - 15

  • 3b ≤ 15

  • b ≤ 15/3

  • b ≤ 5
semsee45

Answer:

15 + 3b ≤ 30

Kayla can buy no more than 5 bangle bracelets

Step-by-step explanation:

Let b = number of bangle bracelets

If Kayla bought a necklace for $15, some bangle bracelets for $3 each, and spent no more than $30:

15 + 3b ≤ 30

To solve:

15 + 3b ≤ 30

Subtract 15 from both sides:

⇒ 3b ≤ 15

Divide both sides by 3:

⇒ b ≤ 5

So Kayla can buy no more than 5 bangle bracelets

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