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A car engine burns gas at 495 K and exhausts to the air at 293 K if it ran at the highest possible efficiency and use 10,000 J of input heat how much he would it be rejected into the air? WILL GIVE BRAINLIEST​

Respuesta :

Answer:

5,920 J

Explanation:

Lowest temperature T₂ = 293 K

Highest temperature T₁ = 495 K

Highest possible efficiency e = 1 - T₂/T₁ = 1 - 293/495 = 0.408

Input heat Q₁ = 10,000 J

Find output heat Q₂

e = 1 - Q₂/Q₁

0.408 = 1 - Q₂/10,000

Q₂/10,000 = 1 - 0.408 = 0.592

so

Q₂  = 10,000 x 0.592 = 5,920 J

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