Respuesta :
ANSWER
Both trucks will move together with speed v = 6.67 m/s
so correct answer will be
The speed of the combined vehicles is less than the initial speed of the truck.
EXPLANATION
As we know that there is no external force on the system of two trucks
So here momentum of the two trucks before collision and after collision will remain same
So here we will have
[tex]m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}[/tex]
so here we will have
[tex]v_{1i} = 10 m/s[/tex]
[tex]v_{2i} = 0[/tex]
[tex]m_1 = 2000 kg[/tex]
[tex]m_2 = 1000 kg[/tex]
now we will have
[tex]2000\times 10 + 1000\times 0 = (2000 + 1000) v[/tex]
[tex]v = \frac{20000}{3000} = 6.67 m/s[/tex]
so correct answer will be
The speed of the combined vehicles is less than the initial speed of the truck.
Explanation:
Given that,
Mass of the truck, m₁ = 2000 kg
Mass of the stopped car, m₂ = 1000 kg
Initial speed of the truck, u₁ = 10 m/s
Initial speed of the car, u₂ = 0 (at rest)
As there is no other forces acting on this system, the momentum remains constant. Let v is the combined speed of the system after the collision. So,
[tex]m_1u_1+m_2u_2=(m_1+m_2)v[/tex]
[tex]2000\times 10+1000\times 0=(1000+2000)v[/tex]
v = 6.667 m/s
Therefore, the speed of the combined mass is 6.667 m/s and the speed of the combined mass is less than initial speed.
