The magnitude of a vector with components (15 m , 8 m) is 17 m
Further explanation
Vector is a quantity that has a magnitude and direction.
A vector in a cartesian coordinate is represented by an arrow in which the slope of the arrow shows the direction of the vector and the length of the arrow shows the magnitude of the vector.
A position vector of a point is a vector drawn from the base point of the coordinates O (0,0) to that point.
The addition of two vectors can be done in the following ways:
[tex]\overrightarrow {AB} + \overrightarrow {BC} = \overrightarrow {AC}[/tex]
A negative vector is a vector with the same magnitude but in opposite direction.
[tex]\overrightarrow {AB} = -\overrightarrow {BA}[/tex]
Let's tackle the problem!
If there is a vector with components x and y, then how to find the size of a vector is as follows:
Magnitude of A Vector = [tex]\large {\boxed {\sqrt{x^2 + y^2}} }[/tex]
The magnitude of a vector with components (15 m , 8 m) is :
[tex]\sqrt{15^2 + 8 ^2} = \sqrt{225 + 64} = \sqrt{289} = 17 ~ m[/tex]
Learn more
- Magnitude of A Vector : https://brainly.com/question/5892298
- Vector Operation : https://brainly.com/question/10164712
- Transformation of Vector : https://brainly.com/question/11581004
Answer details
Grade: College
Subject: Physics
Chapter: Vector
Keywords: Equation , Line , Variable , Gradient , Point , Vector , Magnitude , Directiion , Component
