Respuesta :
4a3b5 − 16a5b2 + 12a2b3 = 4 * a^2 * b^2 * ( a*b^3 - 4 * a^3 * + 3 * b^3)
Answer:
[tex]4a^2b^2(ab^3 -4a^3+3b)[/tex]
Step-by-step explanation:
Given : [tex]4a^3b^5 -16a^5b^2+12a^2b^3[/tex]
To Find: Find factored form.
Solution:
[tex]4a^3b^5 -16a^5b^2+12a^2b^3[/tex]
Take 4 as common
[tex]4(a^3b^5 -4a^5b^2+3a^2b^3)[/tex]
Now take [tex]a^2[/tex] as common
[tex]4a^2(ab^5 -4a^3b^2+3b^3)[/tex]
Now take [tex]b^2[/tex] as common
[tex]4a^2b^2(ab^3 -4a^3+3b)[/tex]
Hence The factored form of [tex]4a^3b^5 -16a^5b^2+12a^2b^3[/tex] is [tex]4a^2b^2(ab^3 -4a^3+3b)[/tex]
