Respuesta :
2) Here, 1 Cl2 gives 1 PCl5, so their molar ratio = 1:1
So, if 3 moles of Cl2, are used it will produce 3 moles of PCl5.
In short, Your Answer would be Option C) 3.00 moles
3) Molar ratio = 3 / 3 = 1 : 1
4) As you can see in the reaction, for each that reacts, two are created.
Oxygen moles = 96/16 = 6
So, iron moles = 6/3 * 2 = 4 moles
4 * 55.8 = 223 g [ 55.8 = molar mass of Iron ]
In short, Your Answer would be Option D
5) Molar ratio of C5H12 to CO2 is 1 : 5
So, if 10 CO2 are produced, it needs = 10 / 5 = 2 moles of C5H12
In short, Your Answer would be Option A) 2 moles
Hope this helps!
So, if 3 moles of Cl2, are used it will produce 3 moles of PCl5.
In short, Your Answer would be Option C) 3.00 moles
3) Molar ratio = 3 / 3 = 1 : 1
4) As you can see in the reaction, for each that reacts, two are created.
Oxygen moles = 96/16 = 6
So, iron moles = 6/3 * 2 = 4 moles
4 * 55.8 = 223 g [ 55.8 = molar mass of Iron ]
In short, Your Answer would be Option D
5) Molar ratio of C5H12 to CO2 is 1 : 5
So, if 10 CO2 are produced, it needs = 10 / 5 = 2 moles of C5H12
In short, Your Answer would be Option A) 2 moles
Hope this helps!
Explanation:
1) Answer 2: [tex]PCl_3+Cl_2\rightarrow PCl_5[/tex]
According to reaction, 1 mol of chlorine gas gives 1 mol of [tex]PCl_5][/tex]
Then, 3.00 moles of chlorine gas will give :
[tex]\frac{1}{1}\times 3.00 mol = 3.00 \text{moles of }PCl_5[/tex]
3.00 moles of [tex]PCl_5[/tex] are made.
2) Answer 3:[tex] Fe_2O_3 + 3 CO\rightarrow 2Fe + 3 CO_2[/tex]
Molar ratio is defined ratio of moles of two different substances.
Moles of carbon monoxide gas = 3 mol
Moles of carbon dioxide gas = 3 mol
Molar ratio of [tex]CO to CO_2=\frac{3 mol}{3 mol}=3:3 = 1:1[/tex]
Molar ratio of [tex]CO to CO_2[/tex] is 3:3.
3) Answer 4:[tex] 4Fe_2O_3 +3O_2\rightarrow 2Fe_2O_3[/tex]
Moles of oxygen gas =[tex]\frac{96.0 g}{32 g/mol}=3 mol[/tex]
According to reaction 3 moles of oxygen gas reacts with 4 mol of iron metal.
Then mass of 4 mol of iron metal :4 mol × 55.85 g/mol =223.4 g≈223 g
223 grams of iron was oxidized.
4) Answer 5; [tex]C_5H_{12} + 8O_2\rightarrow 5CO_2 + 6H_2O[/tex]
According to reaction , 5 moles of carbon dioxide are produced by 1 mol of pentane.
Then 10 moles of carbon dioxide will be produced by:
[tex]\frac{1}{5}\times 10 mol=2 mol[/tex] of pentane.
2 moles of pentane would need to be supplied.